All-on-4 Dental Implants Cost in Brownsville, TX (2026)
All-on-4 in Brownsville, TX averages $18,200 per arch ($9,930 – $28,950). Metro-adjusted pricing for Brownsville. Use the calculator below for a personalized estimate.
Dental Implant Cost Calculator
Estimated cost in Texas
$1,880 – $7,240
Average: $4,140
Includes implant, abutment, and crown where applicable. Actual quotes vary by provider.
All-on-4 Price Breakdown in Brownsville, TX
- Four titanium implants: $4,550 – $7,280
- Fixed full-arch prosthesis: $8,190 – $11,830
- Extractions, sedation, temporaries: $800 – $3,500
Estimates based on ADA survey data, regional dental fee reports, and 2026 market adjustments.
| Procedure | Low | Average | High |
|---|---|---|---|
| Single implant | $990 | $2,480 | $4,550 |
| All-on-4 (full arch) | $9,930 | $18,200 | $28,950 |
| Crown (per tooth) | $660 | $1,160 | $1,820 |
| Bone graft (if needed) | $330 | $660 | $1,240 |
Brownsville, TX vs. national average (single implant): national mid $3,000. Last updated: 2026-03-01.
Frequently Asked Questions
How much does All-on-4 cost in Brownsville, TX?
In Brownsville, TX, All-on-4 typically ranges from $9,930 to $28,950, averaging $18,200 per arch in 2026.
Does insurance cover All-on-4?
Most dental plans classify All-on-4 as major restorative work. Coverage is often limited to annual maximums ($1,000–$2,500) unless medically necessary.
Is All-on-4 cheaper than individual implants?
For a full arch, All-on-4 is usually less expensive than placing 8–10 individual implants with separate crowns.