All-on-4 Dental Implants Cost in Cleveland, OH (2026)
All-on-4 in Cleveland, OH averages $20,240 per arch ($11,040 – $32,200). Metro-adjusted pricing for Cleveland. Use the calculator below for a personalized estimate.
Dental Implant Cost Calculator
Estimated cost in Ohio
$1,840 – $7,080
Average: $4,050
Includes implant, abutment, and crown where applicable. Actual quotes vary by provider.
All-on-4 Price Breakdown in Cleveland, OH
- Four titanium implants: $5,060 – $8,096
- Fixed full-arch prosthesis: $9,108 – $13,156
- Extractions, sedation, temporaries: $800 – $3,500
Estimates based on ADA survey data, regional dental fee reports, and 2026 market adjustments.
| Procedure | Low | Average | High |
|---|---|---|---|
| Single implant | $1,100 | $2,760 | $5,060 |
| All-on-4 (full arch) | $11,040 | $20,240 | $32,200 |
| Crown (per tooth) | $740 | $1,290 | $2,020 |
| Bone graft (if needed) | $370 | $740 | $1,380 |
Cleveland, OH vs. national average (single implant): national mid $3,000. Last updated: 2026-03-01.
Frequently Asked Questions
How much does All-on-4 cost in Cleveland, OH?
In Cleveland, OH, All-on-4 typically ranges from $11,040 to $32,200, averaging $20,240 per arch in 2026.
Does insurance cover All-on-4?
Most dental plans classify All-on-4 as major restorative work. Coverage is often limited to annual maximums ($1,000–$2,500) unless medically necessary.
Is All-on-4 cheaper than individual implants?
For a full arch, All-on-4 is usually less expensive than placing 8–10 individual implants with separate crowns.