All-on-4 Dental Implants Cost in Laredo, TX (2026)
All-on-4 in Laredo, TX averages $18,610 per arch ($10,150 – $29,610). Metro-adjusted pricing for Laredo. Use the calculator below for a personalized estimate.
Dental Implant Cost Calculator
Estimated cost in Texas
$1,880 – $7,240
Average: $4,140
Includes implant, abutment, and crown where applicable. Actual quotes vary by provider.
All-on-4 Price Breakdown in Laredo, TX
- Four titanium implants: $4,653 – $7,444
- Fixed full-arch prosthesis: $8,375 – $12,097
- Extractions, sedation, temporaries: $800 – $3,500
Estimates based on ADA survey data, regional dental fee reports, and 2026 market adjustments.
| Procedure | Low | Average | High |
|---|---|---|---|
| Single implant | $1,020 | $2,540 | $4,650 |
| All-on-4 (full arch) | $10,150 | $18,610 | $29,610 |
| Crown (per tooth) | $680 | $1,190 | $1,860 |
| Bone graft (if needed) | $340 | $680 | $1,270 |
Laredo, TX vs. national average (single implant): national mid $3,000. Last updated: 2026-03-01.
Frequently Asked Questions
How much does All-on-4 cost in Laredo, TX?
In Laredo, TX, All-on-4 typically ranges from $10,150 to $29,610, averaging $18,610 per arch in 2026.
Does insurance cover All-on-4?
Most dental plans classify All-on-4 as major restorative work. Coverage is often limited to annual maximums ($1,000–$2,500) unless medically necessary.
Is All-on-4 cheaper than individual implants?
For a full arch, All-on-4 is usually less expensive than placing 8–10 individual implants with separate crowns.